\[ \frac{2s^2\sqrt{3}}{5} \]
++ Jedes neue Dreieck hat \( \frac{1}{9} \) des vorherigen Flächeninhalts +
+\[ N_n = 4^n \]
+\[ \triangle_n = \left(\frac{1}{9}\right)^n \]
++ \[ \Delta A_n = 4^{n-1} \cdot \left(\frac{1}{9}\right)^{n - 1} = + \left(\frac{4}{9}\right)^{n-1} \] +
+\[ A_n = \sum_{k=0}^{n} \left(\frac{4}{9}\right)^k \]
+\[ A = \sum_{n=0}^{\infty} \left(\frac{4}{9}\right)^n \]
++ \[ = \frac{1}{1 - \frac{4}{9}} = \frac{9}{5} = \underline{\underline{1,8}} \] +