From 2440e19fab82f8b4bc17e48162bf00290e99117d Mon Sep 17 00:00:00 2001
From: Hakim El Hattab
Date: Fri, 23 Aug 2013 14:57:11 -0400
Subject: move examples into test/
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examples/assets/image1.png | Bin 21991 -> 0 bytes
examples/assets/image2.png | Bin 10237 -> 0 bytes
examples/barebones.html | 42 ---------
examples/embedded-media.html | 49 -----------
examples/math.html | 185 ----------------------------------------
examples/slide-backgrounds.html | 101 ----------------------
6 files changed, 377 deletions(-)
delete mode 100644 examples/assets/image1.png
delete mode 100644 examples/assets/image2.png
delete mode 100644 examples/barebones.html
delete mode 100644 examples/embedded-media.html
delete mode 100644 examples/math.html
delete mode 100644 examples/slide-backgrounds.html
(limited to 'examples')
diff --git a/examples/assets/image1.png b/examples/assets/image1.png
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Binary files a/examples/assets/image1.png and /dev/null differ
diff --git a/examples/assets/image2.png b/examples/assets/image2.png
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diff --git a/examples/barebones.html b/examples/barebones.html
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- reveal.js - Barebones
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- Barebones Presentation
- This example contains the bare minimum includes and markup required to run a reveal.js presentation.
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- No Theme
- There's no theme included, so it will fall back on browser defaults.
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diff --git a/examples/embedded-media.html b/examples/embedded-media.html
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- reveal.js - Embedded Media
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diff --git a/examples/math.html b/examples/math.html
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- reveal.js - Math Plugin
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- reveal.js Math Plugin
- A thin wrapper for MathJax
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- The Lorenz Equations
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- \[\begin{aligned}
- \dot{x} & = \sigma(y-x) \\
- \dot{y} & = \rho x - y - xz \\
- \dot{z} & = -\beta z + xy
- \end{aligned} \]
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- The Cauchy-Schwarz Inequality
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- A Cross Product Formula
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- \[\mathbf{V}_1 \times \mathbf{V}_2 = \begin{vmatrix}
- \mathbf{i} & \mathbf{j} & \mathbf{k} \\
- \frac{\partial X}{\partial u} & \frac{\partial Y}{\partial u} & 0 \\
- \frac{\partial X}{\partial v} & \frac{\partial Y}{\partial v} & 0
- \end{vmatrix} \]
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- The probability of getting \(k\) heads when flipping \(n\) coins is
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- \[P(E) = {n \choose k} p^k (1-p)^{ n-k} \]
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- An Identity of Ramanujan
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- \[ \frac{1}{\Bigl(\sqrt{\phi \sqrt{5}}-\phi\Bigr) e^{\frac25 \pi}} =
- 1+\frac{e^{-2\pi}} {1+\frac{e^{-4\pi}} {1+\frac{e^{-6\pi}}
- {1+\frac{e^{-8\pi}} {1+\ldots} } } } \]
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- A Rogers-Ramanujan Identity
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- \[ 1 + \frac{q^2}{(1-q)}+\frac{q^6}{(1-q)(1-q^2)}+\cdots =
- \prod_{j=0}^{\infty}\frac{1}{(1-q^{5j+2})(1-q^{5j+3})}\]
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- Maxwell’s Equations
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- \[ \begin{aligned}
- \nabla \times \vec{\mathbf{B}} -\, \frac1c\, \frac{\partial\vec{\mathbf{E}}}{\partial t} & = \frac{4\pi}{c}\vec{\mathbf{j}} \\ \nabla \cdot \vec{\mathbf{E}} & = 4 \pi \rho \\
- \nabla \times \vec{\mathbf{E}}\, +\, \frac1c\, \frac{\partial\vec{\mathbf{B}}}{\partial t} & = \vec{\mathbf{0}} \\
- \nabla \cdot \vec{\mathbf{B}} & = 0 \end{aligned}
- \]
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- The Lorenz Equations
-
-
- \[\begin{aligned}
- \dot{x} & = \sigma(y-x) \\
- \dot{y} & = \rho x - y - xz \\
- \dot{z} & = -\beta z + xy
- \end{aligned} \]
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- The Cauchy-Schwarz Inequality
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- \[ \left( \sum_{k=1}^n a_k b_k \right)^2 \leq \left( \sum_{k=1}^n a_k^2 \right) \left( \sum_{k=1}^n b_k^2 \right) \]
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- A Cross Product Formula
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-
- \[\mathbf{V}_1 \times \mathbf{V}_2 = \begin{vmatrix}
- \mathbf{i} & \mathbf{j} & \mathbf{k} \\
- \frac{\partial X}{\partial u} & \frac{\partial Y}{\partial u} & 0 \\
- \frac{\partial X}{\partial v} & \frac{\partial Y}{\partial v} & 0
- \end{vmatrix} \]
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- The probability of getting \(k\) heads when flipping \(n\) coins is
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- \[P(E) = {n \choose k} p^k (1-p)^{ n-k} \]
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-
-
-
- An Identity of Ramanujan
-
-
- \[ \frac{1}{\Bigl(\sqrt{\phi \sqrt{5}}-\phi\Bigr) e^{\frac25 \pi}} =
- 1+\frac{e^{-2\pi}} {1+\frac{e^{-4\pi}} {1+\frac{e^{-6\pi}}
- {1+\frac{e^{-8\pi}} {1+\ldots} } } } \]
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- A Rogers-Ramanujan Identity
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- \[ 1 + \frac{q^2}{(1-q)}+\frac{q^6}{(1-q)(1-q^2)}+\cdots =
- \prod_{j=0}^{\infty}\frac{1}{(1-q^{5j+2})(1-q^{5j+3})}\]
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- Maxwell’s Equations
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- \[ \begin{aligned}
- \nabla \times \vec{\mathbf{B}} -\, \frac1c\, \frac{\partial\vec{\mathbf{E}}}{\partial t} & = \frac{4\pi}{c}\vec{\mathbf{j}} \\ \nabla \cdot \vec{\mathbf{E}} & = 4 \pi \rho \\
- \nabla \times \vec{\mathbf{E}}\, +\, \frac1c\, \frac{\partial\vec{\mathbf{B}}}{\partial t} & = \vec{\mathbf{0}} \\
- \nabla \cdot \vec{\mathbf{B}} & = 0 \end{aligned}
- \]
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diff --git a/examples/slide-backgrounds.html b/examples/slide-backgrounds.html
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- reveal.js - Slide Backgrounds
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- data-background: #00ffff
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- data-background: #bb00bb
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- data-background: #ff0000
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- data-background: rgba(0, 0, 0, 0.2)
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- data-background: salmon
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- Background applied to stack
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- Background applied to stack
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- Background applied to slide inside of stack
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- Background image
- data-background-size="100px" data-background-repeat="repeat" data-background-color="#111"
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- Same background twice (1/2)
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- Same background twice (2/2)
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